(a) the liquid flow speed _______ m/s (b) the liquid pressure ______ Pa At a sof
ID: 1374765 • Letter: #
Question
(a) the liquid flow speed
_______ m/s
(b) the liquid pressure
______ Pa
Explanation / Answer
Solution:
Area A1 = 8 cm^2
velocity = v1 = 220 cm/s
Area A2 =3.1 cm^2
Velocity v2=?
according to equation of continuity,A1v1 = A2 v2
v2= A1v1/A2 =(8)(220)/(3.1)
= 567.7 cm/s = speed thru the 3.1 cm^2 cross section
now according to bernoulli's principle,
P1+1/2 d xv1^2 = P2 + 1/2 d v2^2
=> P2 = P1+1/2d(v1^2-v2^2)
= (1.4x10^5 ) +1/2(1660) (2.20^2 - 5.68^2)
= 1.17 x 10^5 Pa
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