I already have the answer. I need the calculations for both of them. Thanks in a

Question

I already have the answer. I need the calculations for both of them. Thanks in advance A direct current power supply is connected to a circuit containing one resistor, and 1.5 A is drawn. If a second identical resistor is connected to the power supply in parallel with the first, how much current is drawn from the battery? A. 3.0 A B. 0.75 A C. 1.5 A D. 6.0 A 18. In the circuit shown, with the switch open the capacitors are completely uncharged. The switch is closed for a long time. The current through the circuit is 0.2 A. Determine the potential difference across the capacitor.

Explanation / Answer

Answe 1

I=V/R

V/R = 1.5 ---(1)

Req = R/2

Inew =V/Req

Inew = 2V/R

Inew = 2*1.5 = 3A Option A

Answer 2

when switch is closed for a long time no current flows through the capacitor

So Total resistance = R1 + R2 = R1 + 8

V = 7 V

so current = 7 / ( R1 + 8 ) = 0.2

so R1 = 27 ohm

so potential difference across the capacitor = potential diff across R2 = 8* 7 / ( 8 + 27) = 1.6 V

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