A man is pushing a 50kg Bureau across a rough floor with coefficient of Kinetic
ID: 1373677 • Letter: A
Question
A man is pushing a 50kg Bureau across a rough floor with coefficient of Kinetic Friction 0.5. He applies a Horizontal force of 300N as shown. You are concerned that his pushing force will cause the Bureau to tip over about the axis rotation indicated by X on the bottom right corner of the Bureau. At what height above the floor would be the applied force cause the bureau begin to rotate about the marked axis X? Assume that the Bureau is uniform so that the gravitational force act on the center of the Bureau and that the Kinetic Friction Force and the Normal force act at the location marked by the axis X.
A man is pushing a 50kg Bureau across a rough floor with coefficient of Kinetic Friction 0.5. He applies a Horizontal force of 300N as shown. You are concerned that his pushing force will cause the Bureau to tip over about the axis rotation indicated by X on the bottom right corner of the Bureau. At what height above the floor would be the applied force cause the bureau begin to rotate about the marked axis X? Assume that the Bureau is uniform so that the gravitational force act on the center of the Bureau and that the Kinetic Friction Force and the Normal force act at the location marked by the axis X.Explanation / Answer
Here ,
we will balance the moment of applied force and wwight about the point X
Now ,
50 * 9.8 * 0.40/2 - 300 * h = 0
h = 0.327 m
height above the floor would be the applied force cause the bureau begin to rotate about the marked axis X is 0.327 m
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