Angular Collisions You want to speed up the system of rotating disks. To do this
ID: 1373428 • Letter: A
Question
Angular Collisions
You want to speed up the system of rotating disks. To do this, you throw a ball of mass mb at the two disks that are still rotating together with the same speed. You throw the ball at the disks, and the ball follows the following trajectory as viewed from above.
Now you want to slow the system down, so you decide to throw a mud ball ( mmud = 2.07 kg ) at the system of rotating disks. The trajectory from above looks like this:
Explanation / Answer
Finally both disc will rotate together means with same angular velocity
Using angular momentum (Iw) conservation,
so initial angular momentum = final angular momentum
(9.8 x 14.3) + (12.7 x -18.6) = (9.8 + 12.7)w
w = - 4.27 rad/s
so disc will move with 4.27 rad/s in clockwise direction.
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Initial energy of system = I1 w1^2 /2 + I2 w2^2 / 2
= ( 9.8 x 14.3^2 / 2) + ( 12.7 x 18.6^2 / 2) = 3198.85 J
final energy of system = (9.8 + 12.7) x 4.27^2 /2 = 205.12 J
Thermal energy created = 3198.85 - 205.12 = 2993.73 J
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moment of inertia of disc I = MR^2 /2
9.8 = m1 * 2.91^2 /2
m1 = 2.31 kg
using angular momentum conservation for discs plus ball system,
(9.8 x 14.3) + (12.7 x -18.6) + (1.73 x 1.38 x cos64.9) = (9.8 + 12.7)w + (1.73 x 8.6 x cos73)
w = - 4.42 rad/s
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now using angular momentum conservation again,
(9.8 + 12.7) x -4.42 + ( -2.07 x 12.7 x 1.60) = ( 9.8 + 12.7 + (2.07 x 2.91^2))w
w =- 3.53 rad/s
(minus sign indicates the direction as clockwise direction)
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