lenovo MasteringPhysics HW.1DChGoogle C 8 https://session.masteringph tps:/sessi
ID: 1373192 • Letter: L
Question
Explanation / Answer
deceleration = a = ? g
where ? = coefficient of kinetic friction = 0.2
g = acceleration due to gravity = 9.81 m/s^2
Distance slided = S = 0.2 m
v^2 = 2 a S
v = sqrt( 2 a S )
v = sqrt (2*0.2*9.81*0.2) = 0.885 m/s
Velocity of combined bullet and block after collision = v = 0.885 m/s
Applying Conservation of momentum
m1 u = ( m1 + m2) v
0.006 u = ( 0.006 + 1.3)*0.885
u = ( 0.006 + 1.3)*0.885 / 0.006 = 192.64 m/s
Initial speed of the bullet = u = 192.64 m/s
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