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lenovo MasteringPhysics HW.1DChGoogle C 8 https://session.masteringph tps:/sessi

ID: 1373192 • Letter: L

Question


lenovo MasteringPhysics HW.1DChGoogle C 8 https://session.masteringph tps:/session masteringphysics.com/myct/itemview-2assignmentProblemiD-43570777 Spring 2015, PHYS 1111/1113, Sections A / BB-EE Signed in HW.102n-8) Problem 8.25 Problem 8.25 Part A 6.00g bullet is fired horizontally into a 1.30kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0 200 The bullet remains embedded in A What was the initial speed of the builet? the block, which is observed to slide 0 200m along the surface before stopping m/s Submit AnswerS SIve Incorrect Try Again; 2 attempts remaining Proy

Explanation / Answer

deceleration = a = ? g

where ? = coefficient of kinetic friction = 0.2

g = acceleration due to gravity = 9.81 m/s^2

Distance slided = S = 0.2 m

v^2 = 2 a S

v = sqrt( 2 a S )

v = sqrt (2*0.2*9.81*0.2) = 0.885 m/s

Velocity of combined bullet and block after collision = v = 0.885 m/s

Applying Conservation of momentum

m1 u = ( m1 + m2) v

0.006 u = ( 0.006 + 1.3)*0.885

u = ( 0.006 + 1.3)*0.885 / 0.006 = 192.64 m/s

Initial speed of the bullet = u = 192.64 m/s