2). What is the horizontal component of the force exerted by the wall on the rod

Question

2). What is the horizontal component of the force exerted by the wall on the rod?

3). What is the vertical component of the force exerted by the wall on the rod?

A 60.0 kg uniform square sign of side 2.10 m, is hung from a 3.15 m rod of negligible mass. A cable is attached to the end of the rod and to a point on the wall 3.00 m above the point where the rod is fixed to the wall. What is the tension in the cable? What is the horizontal component of the force exerted by the wall on the rod? What is the vertical component of the force exerted by the wall on the rod?

Explanation / Answer

First, the triangle between the rod and the cable is a 3.15/3/5.25 triangle,

so sin theta = 3/5.25,

cos theta = 3.15/5. (theta is the angle between the rod and the cable at the end with te wieght.)

The sum of the forces in the y-direction means that T * sin theta = 50 kg * gravity.

So T = (60 kg * gravity) / sin theta
T = (60 kg * 9.81 m/s^2) / (3/5.25)

T=1029 N

b)use the sum of forces in the x-direction to get the Compression in the rod

R=T*cos theta
R=T*3.15/5

R=1029*3.15/5
R=648.27 N Opposite direction as Tension in cable so it is compression.

c)here is no vertical forces on the rod because it is hinged. Only Horizontal.

Related Questions

Navigate

• Browse (All)
• Browse 2
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.