When only a resistor is connected across the terminals of an ac generator (110 V

Question

When only a resistor is connected across the terminals of an ac generator (110 V) that has a fixed frequency, there is a current of 0.455 A in the resistor. When only an inductor is connected across the terminals of this same generator, there is a current of 0.428 A in the inductor. When both the resistor and the inductor are connected in series between the terminals of this generator, calculate the following.

(a) the impedance of the series combination.

(b) the phase angle between the current and the voltage of the generator.

Explanation / Answer

a)

When the resistor is connected across the terminals ofthe battery then the current is

                         i = ?/R

                        0.455 A=110 V/R

R = 241.76 ?

When the inductance of the inductor is connected across theterminals of the battery then the current is

                        0.428 =110 V/XL

XL =257 ?

Then the resistor and inductor are conncected in series thenthe impedance of the series combination is

                       Z =?R2 +XL2

                          = 352.84 ?

b)

The phase angle between the current and the voltage ofthe generator is

                      Tan? = (XL/R)

                            ? =Tan-1(257/241.76)

                                =46.750

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