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Consider a glancing collision between two identical spheres of 0.012 kg, with on

ID: 1372578 • Letter: C

Question

Consider a glancing collision between two identical spheres of 0.012 kg, with one of the spheres initially at rest. Initially the incoming projectile has a velocity of 1.30 m/s to the right and after the collision we observe that this sphere leaves the collision region with a velocity of 0.50 m/s at an angle of 29 degree to its initial direction. (Assume that the +x-axis is to the right and the +y-axis is up along the page. Angles are measured counterclockwise from the +x-axis. Do not assume this collision is elastic.) (a) Find the x-component of the velocity of the second sphere. (b) Find the y-component of the velocity of the second sphere.

Explanation / Answer

Here momentum is conserved and the masses are the same so they cancel
leaving this vector sum
V1i = V1f + V2f
we must assume that the 29° given is CCW from x-axis
(1.30 , 0 ) = (0.50 cos29 , 0.50 sin29) + (x , y)
(1.30 , 0) = (0.44 , 0.24) + (x , y)
(x , y) = (1.30-0.44 , 0-0.24) = (0.86 , -0.24) these are the x and y components of v of 2nd sphere

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