Suppose you weigh 723 N, and when you stand on one foot, your weight is spread o

Question

Suppose you weigh 723 N, and when you stand on one foot, your weight is spread out over an area of 1.060×10-2 m2. What pressure does your foot exert on the floor? (Check out the book or online for the correct unit. Remember that there is also a blue help button if the units are inconsistent.)

Atmospheric pressure is around 1.010×105 Pa. Think about the air pushing on a flat, circular glass window which has a radius of 0.103 m. What is the force with which the air is pushing on one side of the glass?

Explanation / Answer

weight is balanced by 1 foot
F = 723 N
A = 1.06*10^-2 m^2
P = F/A
= 723 N/ (1.06*10^-2 m^2)
= 6.82*10^4 N/m^2
= 6.82*10^4 Pa

--------------------------------------------------------------
P = 1.01*10^5 Pa
Area, A = pi*r^2
= pi* (0.103)^2
= 0.033 m^2

F = P*A
= 1.01*10^5 * 0.033
= 3366 N

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