1. What is the impulse on a 4.0 kg particle that experiences the force described

Question

1. What is the impulse on a 4.0 kg particle that experiences the force described by the graph in the figure? F (N) 2. Consider an inelastic collision between a 1 Kg cart moving to the right at 2 m/s and a 2 Kg cart moving to the left at 4 m/s. What is the speed and direction of the 2 carts after they have stuck together? 3. A mass in1 traveling to the right with a speed y1 makes a glancing collision with a mass m initially at rest. After the collision the masses have speeds v1 and v2 and move in directions qi and q. as shown below. Determine the velocity of m2 after collision (i.e. find v2')

Explanation / Answer

Q 1

Area under the f-t curve gives impulse. area below the t axis is negative and above the t axis is positive

here we have three rectangles

two rectangles below t axis and one above t axis

time is in milisecod so we convert it to seconds

area of first rectangle = -(1000 * 3x10^-3) = -3 N-s

area of second rectangle = 2500 x 9 x10^-3 = 22.5 N-s

area of third traingle = -1000* 3x10^-3 = -3 N-s

total impulse = -3+22.5-3

impulse = 16.5 N-s

Q 2

by conservation of momentum

m1v1 + m2v2 = (m1+m2)V

V = m1v1 + m2v2 /(m1+m2)

considering right as positive

V =( 1*2 - 2*4) /(1+2)

V = - 2 m/s

so speed of carts is 2m/s and move towartds left direction

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