Part A Compute the torque developed by an industrial motor whose output is 185 k

Q: Part A Compute the torque developed by an industrial motor whose output is 185 k

Power output = 185kW = 185*10^3 W w = 5000 rev/min = 5000*2*pi/60 = 523.6 rad/s A) We know, Power = Torque*angular velocity P = T*w ==> T = P/w = 185*10^3/(523.6) = 353.3 N.m B) T = W*R ==> W = T/R = 353.2/(0.46/2) = 384 kg C) v = R*w = (0.46/2)*523.6 = 120.4 m/s

ID: 1369946 • Letter: P

Question

Part A Compute the torque developed by an industrial motor whose output is 185 kW at an angular speed of 5000 rev/min .
Part B

A drum with negligible mass, 0.460 m in diameter, is attached to the motor shaft, and the power output of the motor is used to raise a weight hanging from a rope wrapped around the drum. How heavy a weight can the motor lift at constant speed? Part C At what constant speed will the weight rise? Part A Compute the torque developed by an industrial motor whose output is 185 kW at an angular speed of 5000 rev/min .
Part B

A drum with negligible mass, 0.460 m in diameter, is attached to the motor shaft, and the power output of the motor is used to raise a weight hanging from a rope wrapped around the drum. How heavy a weight can the motor lift at constant speed? Part C At what constant speed will the weight rise? Part A Compute the torque developed by an industrial motor whose output is 185 kW at an angular speed of 5000 rev/min .
Part B

Part A Compute the torque developed by an industrial motor whose output is 185 kW at an angular speed of 5000 rev/min .
Part B

Part B

Part B

Part B
A drum with negligible mass, 0.460 m in diameter, is attached to the motor shaft, and the power output of the motor is used to raise a weight hanging from a rope wrapped around the drum. How heavy a weight can the motor lift at constant speed? A drum with negligible mass, 0.460 m in diameter, is attached to the motor shaft, and the power output of the motor is used to raise a weight hanging from a rope wrapped around the drum. How heavy a weight can the motor lift at constant speed? Part C At what constant speed will the weight rise? Part C At what constant speed will the weight rise?
Part B

Explanation / Answer

Power output = 185kW = 185*10^3 W

w = 5000 rev/min = 5000*2*pi/60 = 523.6 rad/s

A) We know, Power = Torque*angular velocity

P = T*w

==> T = P/w

= 185*10^3/(523.6)

= 353.3 N.m

B) T = W*R

==> W = T/R

= 353.2/(0.46/2)

= 384 kg

C) v = R*w

= (0.46/2)*523.6

= 120.4 m/s

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Part A Compute the torque developed by an industrial motor whose output is 185 k

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Part A Compute the torque developed by an industrial motor whose output is 185 k

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