. The earth\'s magnetic field at your location is horizontal and equal to 8.0×10

Question

. The earth's magnetic field at your location is horizontal and equal to 8.0×105T, and you decide to try to use this field for a generator by rotating a large circular coil of wire at a high rate. You need to produce max = 9.0V and estimate that you can rotate the coil at 30rpm by turning a crank handle. You also decide that to have an acceptable coil resistance, the maximum number of turns the coil can have is 2000. Part A What area must the coil have? Part B If the coil is circular, what is the maximum translational speed of a point on the coil as it rotates?

Explanation / Answer

angular speed w = 30 rpm = 30 x 2pi rad / 60 sec = 3.14 rad/s

e_max = NABw

9 = 200 x A x 8 x 10^-5 x 3.14

A = 179.05 m^2

if coil is circular,

then pi r^2 = 179.05

r = 7.55 m

v = wr =3.14 x 7.55 =23.73 m/s

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