torque. The rope on the pulley has two different radii....Im lost and dont reall
ID: 1369643 • Letter: T
Question
torque.
The rope on the pulley has two different radii....Im lost and dont really understand torque, any help would be apreciated
2, Now the handixsremoved and the ysmisfr to clerate Hin Now the hand is removed and the system is free to accelerate. (Hint: For all of the questions below, draw a free body diagram.) 2) i) Determine the acceleration directions (if any) for the disk and both masses. Explain ii) How do the tensions, Ti and T2 compare to each other now? Explain i) fdow does ite ensiwhen the tand is removed? Explain. iv) How does the tension, T2, change, if at all, when the hand is removed? Explain. Ti T2 v) What is wrong with the following student's rasoning? v) What is wrong with the following student's reasoning? 1n "The torque into the page is greater than the torque out of the page because the disk is accelerating into the page (in a clockwise rotational sense as depicted). For this to happen, T2 must pull harder on the disk than Ti." happen, 72 must pull harder on the disk than Ti vi) Notice that "into-the-page" indicates a direction whereas "clockwise" does not. Since torque, angular velocity and angular acceleration are vectors, explain why "clockwise" is not a good way to describe them. vii) A person standing at the Earth's North Pole observes the Earth to rotate with a counter-clockwise sense of motion (when staring at the ground). A person standing at the Earth's South Pole observes the Earth to rotate with a clockwise sense of motion. What actual compass direction is the Earth's angular velocity pointing?Explanation / Answer
Suppose the inner radius of the pulley is R1 and the outer radius is R2 then the torque due to T1 will be T1 times the radius R1 and in anti clockwise direction. Similarly torque due to T2 will be T2 times the radius R2 but in the clockwise direction.
The torque about an axis by definition is given by the cross product of R and F, where R is the position vector pointing towards the perpendiculer drawn on the line of action of force F and F is the force applied.
Explanation: Suppose we want to calculate torque due to force T1 which is vertically downward. The first we will find the direction of the torque by the right hand thumb rule. We will put our fingers in the direction of R which is towards left and then try to fold towards force T1 then we get direction to be anticlockwise. Once we get the direction, we calculate the magnitude which is nothing but force time the perpendicular distance. So we get the torque T1R1 in anticlockwise direction. Simlarly for force T2. The torque due to both combined will be T2*R2-T1*R1 in clockwise direction.
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