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EdtVew History Bookmarks People Window Help https://s bemView?assi P100AFL15 Signad in as fozad ardagh Helo previous 1 of 10 ne Part A The figures below show brds-eye viows of six automobile crashes an ihstant boore they ooour. The audomobiles have dierent masses and incoming velooiies as shown. After impact, the automobles remain joined together and skid to nest in the direction shown by thisal Rank these crashes according to the angie 8, countarclockwise as shown, at which to wreckage initaly skids Rank from largest to smallest. To rank items as equivalent, overlap them 0 m's 0o0 kg 00 kg l0 m/ 700 k 1000 kg 1500 k 1000 kg MacBook Pro 8 command optionExplanation / Answer
m1 = 1200 kg
m2 = 700 kg
before collision
u1x = 9 m/s u2y = 15 m/s
after collision m1 , m2 combine and move with speed V1
fom momentum conservation
initial momentum = final momentum
along x
m1*u1x + m2*u2x = (m1+m2)*V1x
1200*9 = (1200+700)*v1x
V1x = 5.68 m/s
along y
m1*u1y + m2*u2y = (m1+m2)*v1y
0 + 700*15 = (1200+700)*v1y
v1y = 5.53 m/s
theta1 = arctan(v1y/v1x) = arctan(5.53/5.68)
theta 1 = 44.23
--------------------------------------
m1 = 700 kg
m2 = 700 kg
before collision
u1x = 7 m/s u2y = 7 m/s
after collision m1 , m2 combine and move with speed V2
fom momentum conservation
initial momentum = final momentum
along x
m1*u1x + m2*u2x = (m1+m2)*V2x
700*7 = (700+700)*v2x
V2x = 3.5 m/s
along y
m1*u1y + m2*u2y = (m1+m2)*v2y
0 + 700*7 = (700+700)*v2y
v2y = 3.5 m/s
theta2 = arctan(v1y/v1x) = arctan(3.5/3.5)
theta 2 = 45
--------------------------------------
m1 = 1000 kg
m2 = 1000 kg
before collision
u1x = 10 m/s u2y = 7 m/s
after collision m1 , m2 combine and move with speed V3
fom momentum conservation
initial momentum = final momentum
along x
m1*u1x + m2*u2x = (m1+m2)*V3x
1000*10 = (1000+1000)*v3x
V3x = 5 m/s
along y
m1*u1y + m2*u2y = (m1+m2)*v3y
0 + 1000*7 = (1000+1000)*v3y
v3y = 3.5 m/s
theta3 = arctan(v3y/v3x) = arctan(3.5/5)
theta 3 = 35
--------------------------------------
m1 = 1000 kg
m2 = 1500 kg
before collision
u1x = 15 m/s u2y = 10 m/s
after collision m1 , m2 combine and move with speed V4
fom momentum conservation
initial momentum = final momentum
along x
m1*u1x + m2*u2x = (m1+m2)*V4x
V4x = m1*u1x/(m1+m2) m/s
along y
m1*u1y + m2*u2y = (m1+m2)*v4y
v4y = m2*u2y/(m1+m2) m/s
theta4 = arctan(v4y/v4x) = arctan((m1*u2y)/(m1*u1x))
theta 4 = arctan(1000*10/(1000*15))
theta4 = 33.7
--------------------------------------
m1 = 1000 kg m2 = 1000 kg
before collision
u1x = 7 m/s u2y = 10 m/s
after collision m1 , m2 combine and move with speed V5
fom momentum conservation
initial momentum = final momentum
along x
m1*u1x + m2*u2x = (m1+m2)*V5x
V5x = m1*u1x/(m1+m2) m/s
along y
m1*u1y + m2*u2y = (m1+m2)*v5y
v5y = m2*u2y/(m1+m2) m/s
theta5 = arctan(v4y/v4x) = arctan((m1*u2y)/(m1*u1x))
theta 4 = arctan(1000*10/(1000*7))
theta4 = 55
------------------------
m1 = 1000 kg
m2 = 1000 kg
before collision
u1x = 10 m/s u2y = 10 m/s
after collision m1 , m2 combine and move with speed V6
from momentum conservation
initial momentum = final momentum
along x
m1*u1x + m2*u2x = (m1+m2)*V6x
V6x = (m1*u1x)/(m1+m2) m/s
along y
m1*u1y + m2*u2y = (m1+m2)*v6y
V6y = (m1*u2y)/(m1+m2)
theta6 = arctan(v6y/v6x) = arctan(10/10)
theta 6 = 45
--------------------------------------
5 > 2 = 6 > 1 > 3 > 4
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