A. The charge starts at zero and increases to some maximum value; the bulb start
ID: 1368777 • Letter: A
Question
A. The charge starts at zero and increases to some maximum value; the bulb starts bright and dims over time.
B. The charge and the brightness start at zero and continue to increase over time (never reaching a maximum value).
C. The charge starts large and decreases to zero over time; the bulb starts dim and brightens, reaching a maximum brightness.
D. The charge starts at zero and increases to a maximum value; the bulb starts dim and brightens, reaching a maximum brightness.
E. The charge starts large and decreases to zero over time; the bulb starts bright and dims over time.
(b) Now open the bottom switch and close the top one. What happens to the charge on the capacitor and the brightness of the bulb as a function of time?
A. The charge decreases over time while the brightness of the bulb increases over time.
B. The charge and brightness both increase from zero over time.
C. The charge increases over time while the brightness of the bulb decreases over time.
D. The charge and brightness both decrease to zero over time.
(c) What statement below best characterizes when you will see the light bulb light (i.e., current in the circuit)?
A. The light bulb lights only when the capacitor is discharging.
B. The light bulb lights when the capacitor is uncharged.
C. The light bulb lights only when the capacitor is charging.
D. The light bulb lights when the capacitor is charged.
E. The light bulb lights only when the capacitor begins charging or discharging.
(d) From your observations, estimate the time scale for this circuit.
A. 1/5 second
B. 5 seconds
C. 1 second
D. 3 seconds
E. 1/3 second
F. 10 seconds
(e) Now add the voltage chart (measure the voltage across C) and the current chart (measure the current through C). With the top switch open, close the bottom switch. What happens to the voltage across the capacitor & the current through the capacitor as a function of time?
A. The voltage across C increases from zero and saturates the the voltage of the battery; the current starts at zero and saturates to a maximum value.
B. The voltage across C exponentially decays to zero; the current starts at zero and saturates to a maximum value.
C. The voltage across C increases from zero and saturates the the voltage of the battery; the current exponentially decays to zero.
D. The voltage across C exponentially decays to zero; the current exponentially decays to zero.
E. The voltage across C exponentially decays to zero; the current remains constant.
F. The voltage across C increases from zero and saturates the the voltage of the battery; the current remains constant.
(f) Now open the bottom switch and close the top one. What happens to the voltage across the capacitor & the current through the capacitor as a function of time?
A. The voltage across C exponentially decays to zero; the current starts at zero and saturates to a maximum value.
B. The voltage across C exponentially decays to zero; the current remains constant.
C. The voltage across C exponentially decays to zero; the current exponentially decays to zero.
D. The voltage across C increases from zero and saturates the the voltage of the battery; the current starts at zero and saturates to a maximum value.
E. The voltage across C increases from zero and saturates the the voltage of the battery; the current exponentially decays to zero.
F. The voltage across C increases from zero and saturates the the voltage of the battery; the current remains constant.
(g) Control-click on the capacitor and change its C to 0.2 F. What happens to its time constant for charging/discharging?
A. The time constant quadruples
B. The time constant is reduced by a factor of 4
C. The time constant doubles
D. The time constant is unchanged
E. The time constant halves
Explanation / Answer
c)
E. The light bulb lights only when the capacitor begins charging or discharging.
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