A 30.0-kg block is resting on a flat horizontal table. On top of this block is r

Question

A 30.0-kg block is resting on a flat horizontal table. On top of this block is resting a 10.0-kg block, to which a horizontal spring is attached, as the drawing illustrates. The spring constant of the spring is 305 N/m. The coefficient of kinetic friction between the lower block and the table is 0.400, and the coefficient of static friction between the two blocks is 0.710. A horizontal force is applied to the lower block as shown. This force is increasing in such a way as to keep the blocks moving at a constant speed.
Determine the amount by which the spring is compressed at the point where the upper block begins to slip on the lower block. (in m)

Explanation / Answer

KX = um2g

=> 305*X = 0.710*10*9.8

=> X = 0.228 m

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