If you have five capacitors with capacitances 1×10 -6 F, 2.2×10 -6 F, 3.7×10 -6

Question

If you have five capacitors with capacitances 1×10-6 F, 2.2×10-6 F, 3.7×10-6 F, and two 9.1×10-6 F in series.

1)What is the equivalent capacitance of all five?

C =

2)Initially the capacitors are uncharged. Now a 10 V battery is attached to the system. How much charge is on the positive plate of the 3.7×10-6 F capacitor?

Q =

3)What is the potential difference between the plates of the 3.7×10-6 F capacitor?

V =

4) How much energy is stored in the entire capacitor system?

PE =

5) If you have five capacitors with capacitances 1×10-6 F, 2.2×10-6 F, 3.7×10-6 F, and two 9.1×10-6 F in parallel. What is the equivalent capacitance of all five? What is the equivalent capacitance of all five?

C =

6) If one attaches a 10 V battery is attached to the system. How much charge is on the positive plate of the 3.7×10-6 F capacitor?

Q =

7) What is the potential difference between the plates of the 9.1×10-6 F capacitor?

V =

8) How much energy is stored in the entire capacitor system?

PE =

Please Help!

Explanation / Answer

1.

the equivalent capacitance of all caapacitors when they connected in series:

1/C = [1/C1+1/C2+1/C3+1/C4+1/C5]

C = [1/C1+1/C2+1/C3+1/C4+1/C5]-1

= 5.14e-7 F

= 0.514e-6 F

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