A particularly large playground merry-go-round is essentially a uniform solid di
ID: 1368466 • Letter: A
Question
A particularly large playground merry-go-round is essentially a uniform solid disk of mass 3M and radius R that can rotate with no friction about a central axis. You, with a mass M, are a distance of R/2 from the center of the merry-go-round, rotating together with it at an angular velocity of 3.20 rad/s clockwise (when viewed from above). You then move to the outside of the merry-go-round so you are a distance R from the center, still rotating with the merry-go-round. Consider you and the merry-go-round to be one system.
(a) When you reach the outer edge of the merry-go-round, what is the angular velocity of the you and merry-go-round system?
(b) You then start running around the outer edge of the merry-go-round. At what angular speed would you have to run to make the merry-go-round alone come to a complete stop?
Explanation / Answer
a) initial moment of inertia = 3M R^2 /2 + (M ( R/2)^2) = 7MR^2 / 4
final momentum of inertia = (3M R^2 /2 ) + ( MR^2) = 5MR^2 /2
Using momentum conservation,
Iwi = I ( wf)
( 7MR^2 / 4 ) x 3.20 = ( 5MR^2 /2 ) wf
wf = 2.24 rad/s
b) Applying angular momentum conservation,
( 7MR^2 / 4 ) x 3.20 = 0 + ( M R^2) w
w = 5.6 rad /s
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.