An object of mass .550kg is lifted from the floor to a height of 3.50m at a cons

Question

An object of mass .550kg is lifted from the floor to a height of 3.50m at a constant speed.
A) how much work is done by the lifting force (include units)?
B) how much work is done by the earth on the object?
C) what is the net work done on the object?
D) what is the change in kinetic energy on the object?
E) are your results consistent with the work-energy principle? Explain.
Please show the work too so I can see how to do it. An object of mass .550kg is lifted from the floor to a height of 3.50m at a constant speed.
A) how much work is done by the lifting force (include units)?
B) how much work is done by the earth on the object?
C) what is the net work done on the object?
D) what is the change in kinetic energy on the object?
E) are your results consistent with the work-energy principle? Explain.
Please show the work too so I can see how to do it.
A) how much work is done by the lifting force (include units)?
B) how much work is done by the earth on the object?
C) what is the net work done on the object?
D) what is the change in kinetic energy on the object?
E) are your results consistent with the work-energy principle? Explain.
Please show the work too so I can see how to do it.

Explanation / Answer

part a )

Fnet on system = 0 because there is no acceleration

part a )

w = mgh

w = 0.55 * 9.8 * 3.5 = 18.865 J

part b )

by earth force is downward

w = -mgh = -18.865 J

part c )

w = 0 J

Fnet = 0

and w = F.d

part d )

no change in kinetic energy during lifting because object moving with cosntant speed .

part e )

the work done by our lift force exactly matched that done by gravity. If we only considered the work done by the lift force, we would say the potential energy in the gravitational field increased by mgh.

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