As long as you don’t stretch it too much, the force exerted by the spring obeys
ID: 1366838 • Letter: A
Question
As long as you don’t stretch it too much, the force exerted by the spring obeys Hooke’s Law. The further you stretch the spring, the harder it pulls back on you. The stiffness of a spring is represented by the spring constant (see Section 10.1 in the text). In this problem consider the spring to be of negligible mass. Suppose you stretch a spring 0.0766 m from its equilibrium position. The spring has a spring constant of 1.39×103 N/m. a) What is the magnitude of the force you need to exert on the spring? b) Tries 0/10 Suppose you place this same spring on a hook and hang a 0.526 kg object on the end. How far does the spring stretch from equilibrium? (think about the force that the object exerts on the spring).
Explanation / Answer
a)
F = K*x
= (1.39*10^3)*(0.0766)
=106.5 N
b)
here force acting = m*g = 0.526*9.8 =5.155 N
F= K*x
5.155 = (1.39*10^3)*x
x=3.71*10^-3 m
Answer: 3.71*10^-3 m
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