To practice Problem-solving Strategy 7.1 for interaction-objects problems. A 120

Question

To practice Problem-solving Strategy 7.1 for interaction-objects problems. A 1200 -kg car is pushing an out-of-gear 2200 -kg truck that has a dead b32ery. When the driver steps on the accelerator, the d rive wheels of the car push horizontally against the g round with a force of 4520 N . The rolling friction of the car can be neglected, but the heavier truck has a rolling friction of 760 N . including the "friction" of turning the truck's divert in. What is the magnitude of the force the car applies to the truck?

Explanation / Answer

let a = acceleration of the car and truck together
total m = 1200 + 2200 = 3400kg
total F = 4520 - 760 = 3760 N
a = 3760/3400 = 1.106 m/s2
so the force from the car on the truck = 4520 - 1200 a
F on truck = 4520 - 1200 (1.106)
F on truck = 3193 Newtons

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