Valerie and Jake are performing the 1-D Collisions experiment. They measure the

Question

Valerie and Jake are performing the 1-D Collisions experiment. They measure the mass of glider A to be 255 g and its length to be 17.3 cm. The same properties of glider B are 252 g and 17.2 cm. Val pushes glider A through photogate #1, and Jake reads the transit time from the computer display as 0.49 seconds. What is the speed of glider A, in m/s, as it passed through the photogate? Jake pushes glider B through photogate #2 and calculates its speed to be 0.45 m/s. What is the momentum of glider B in kg m/s? Val and Jake run one of the four scenarios described in the Procedure section. They add an additional 50.0 g of mass to glider B and start the experiment with glider B initially at rest. They measure the time for glider A to pass through photogate #1 to be 0.258 s. The collision occurs and glider A rebounds, going backwards through photogate #1 with a transit time of 2.883 s, while glider B passes forward through photogate #2 with a transit time of 0.282 s. Calculate the total momentum of gliders A and B after the collision in kg m/s. In the trial run in PL-3, what is the total kinetic energy, in Joules, of gliders A and B before the collision?

Explanation / Answer

1) vA = L / t = 17.3 cm / 0.49s =35.31 cm/s = 0.353 m/s

2) momentum = mv

m = 0.252 kg and v 0.45 m/s

momentum = 0.252 x 0.45 =0.113 kg m/s

3) momentum after the collision,

Glider A : vA = 0.173 m / 2.883s =0.06 m/s
momentum = 0.255 x 0.06 = - 0.0153 kg m/s

Glider B: vB = 0.172 / 0.282 =0.61 m/s

momentum = (0.252 + 0.050) x 0.61 =0.184 kg m/s

total momentum = 0.167 kg m/s

4)before collision,
vA = 0.173 / 0.258 = 0.670 m/s

vB = 0

initial KE = 0 + 0.255 x 0.67^2 /2 =0.057 J

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