If you replace +40 ?C charge above with a -80 ?C charge, what happens to the the

ID: 1361199 • Letter: I

Question

If you replace +40 ?C charge above with a -80 ?C charge, what happens to the the electric field that q1 creates at the spot occupied by q2?

Question 1 options:

Since both charges are the same sign, q1 doesn't create any electric field at the spot occupied by q2.

It doesn't change.

It doubles in magnitude and reverses direction.

It reverse direction but does not change in magnitude.

It doubles in magnitude but does not reverse direction.

Since both charges are the same sign, q1 doesn't create any electric field at the spot occupied by q2.

It doesn't change.

It doubles in magnitude and reverses direction.

It reverse direction but does not change in magnitude.

It doubles in magnitude but does not reverse direction.

electric field due to a positive charge is directed away from it and electric field due to a negative charge is directed towards it.

magnitude of electric field due to a charge q at a distance of d is given by

E=k*q/d^2

so when we replace 40 uC by a -80 uC charge, charge magnitude becomes double and distance remains the same

hence magnitude of electric field gets doubled.

also, as -80 uC is of opposite sign to that of 40 uC, the direction of electric field also changes.

hence third option is the correct answer.

It doubles in magnitude and reverses direction.

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