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Homework&M; H 12566559 y C Q Search ent emailDO1.Brightspace Student eServices Erporee ornal Erployee email Facury eServices StarD Sef Service negative. Need Help? RaadIt -2 points SePSET99P:033. My Notes Notes O OAsk Your Te Two blocks are free to slide along the frictionless wooden track shown below. The block of mass m -4.99 kg is released from the position shown, at height h 5.00 m above the flat part of the track. Protruding from its front end is the north pole of a strong magnet, which repels the north pole of an identical magnet embedded in the back end of the block of mass m2 9.5o kg, initially at rest. The two blocks never touch. Calculate the maximum height to which m nises after the elastic collision. Your Teacha Three carts of masses m -5.00 kg, m2-12.00 kg, and m 3.00 kg move on a frictionless, horizontal track with speeds of vi- 4.50 m/s to the right, v2 the right, and vs - 3.50 m/s to the left, as shown below. Velcro couplers make the carts stick together after colliding 3.00 m/s to

Explanation / Answer

speed of m1 before collision

using energy conservation

mgh = 1/2*mv^2

vi = sqrt(2gh)

in elastic collision

v1f = v1i*(m1-m2)/(m1+ m2) + (2m2 / m1 + m2) * v2i

here 2nd block was at rest initially

v1f = v1i * (m1-m2) / (m1 + m2)

v1f = sqrt(2gh) * (m1-m2) / (m1+m2)

now apply again energy conservtion after collision

1/2*m1* 2gh * [(m1-m2) / ( m1+m2)^2 = m1*g*h'

h' = [(m1 -m2) / ( m1+m2)] ^2 * h

given m1 = 4.99 kg

m2 = 9.5 kg

h = 5 m

h' = 0.484 m

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