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Question

tudent/Assignment dep-12565589 C Search tudentenal O2L Bngntspace Studont eSer nces ] Employee emal sl Faculty eSences StarD Set Sevice . : Need Help? Mends eed Help?Read It 3. -12 points SerPSET99.P 014 After a 0.310-kg rubber ball is dropped from a height of 19.0 m, it bounces off a concrete floor and rebounds to a height of 45.5 m. (a) Determine the magnitude and direction of the impulse delivered to the bal by the floor direction-Select magnitude kg m/s (b) Estimate the time the ball is in contact with the floor to be o.04 seconds. Calculate the average force t magnitude direction Select he floor exerts on the ball. Need Help? eaIn Read It 40 2.4 points SerPSET9 9.P017 MISA This question has several parts that must be completed sequentialy. Ir you skip a part of the question, you will not recesive any points for the sk to the skipped part. several parts that must be completed sequentily, It you op pont ns tor the sk Tutorial Exercise The front 1.20 m of a 1.601-kg car is designed as a "crumple zone" that collapses to absorb the shock of a collision

Explanation / Answer

part a )

Impulse = change in momentum

Falling from a 19 m will give the speed at the moment the ball hits the floor

v = sqrt(2gh )

v = 19.3 m/s in - y direction

Bouncing up to 1.55m will give the speed at the moment the ball bounces up

v = sqrt(2gh)

v = sqrt(2*9.8*15.5)

v = 17.43 m/s in +y direction

Impulse = m (vf - vi )

Impulse = 0.310 ( 17.43 - (-19.3) )

Impulse = 11.39 kg. m/s

direction = upward

part b )

F =dP/dt

F = 11.39 / 0.04

F = 284.75 N

direction = upwards

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