You have two conducting plates with nothing in between them. Using a voltmeter,

Question

You have two conducting plates with nothing in between them. Using a voltmeter, you measure the voltage difference between the plates to be 455 V. You release an alpha particle with mass of 6.5 times 10^-27 kg and a charge of 3.2 Times 10^-19 C from near the positive plate. What is the kinetic energy of the alpha particle when it reaches the other plate? The distance between the plates is 26.0 cm. You observe an electron move through a uniform electric field. The electron field-system loses 4260 pJ of electrostatic potential energy as the electron picks up speed. What was the voltage difference between the two points? You build a capacitor using two concentric spheres. The outer sphere has 2 tunes the radius of the inner one. You measure the capacitance to be 8.00 pF and the voltage difference between the spheres to be 64.0 V. You'd like to figure out how much energy is stored in the capacitor. How much charge is on the capacitor's positive plate? You construct a parallel plate capacitor with a plate spacing of 1.40 cm and a capacitance of 5.30 mu F. A friend of yours doubles the spacing between the plates and puts a dielectric between them. This changes the capacitance to 14.5 mu F. What is the dielectric constant of the inserted material? You've set up an electric field that points along the x-axis (the horizontal direction). The x-component of the field is 2.5x^2 in N/C. You want to compute the potential difference between the points (0.0.0) m and (7.3.0.0) m. A heavy summer rain has just spoiled a fun game of frisbee between you and your friends. As you rush to leave, a bolt of lightning strikes a tree on the other side of the field. Lightning is a form of electrical discharge that occurs when the electric field in a region between the ground and the clouds ionizes the air. You happen to know that a bolt of lightning can unleash between a hundred-million and a billion joules of energy, transferring tens of coulombs of charge between the earth and the sky. Out of curiosity, you decide to estimate the magnitude of the associated voltage difference. You estimate that the lightning travelled along a vertical distance of about a mile. You decide to estimate the magnitude of the average electric field strength across tins distance.

Explanation / Answer

1)

Work - energy theorem:

W = KE

So,

KE = QV = ( 2x10^{-19} C )( 455 V ) = 9.1x10^{-17} J

Un electron volts:

KE = 567.977 eV

I can help you with other questions. But you need post again as a new question

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