Q2-The figure shows a cold package of hot dogs sliding rightward across a fricti

Question

Q2-The figure shows a cold package of hot dogs sliding rightward across a frictionless floor through a distance d = 24.0 cm while three forces act on the package. Two of them are horizontal and have the magnitudes F1 = 7.0 N and F2 = 3.0 N; the third is angled down by = 60.0° and has the magnitude F3 = 4.0 N. (a) For the 24.0 cm displacement, what is the net work done on the package by the three applied forces, the gravitational force on the package, and the normal force on the package? (b) If the package has a mass of 2.0 kg and an initial kinetic energy of 0, what is its speed (in m/s) at the end of the displacement?

Explanation / Answer

Here ,

distance , d = 24 cm

let the force is Fnet

Fnet = 7 + 3 + 4 * cos(60)

Fnet = 12 N

net work done on the package = Fnet * d

net work done on the package = 12 * 0.24

net work done on the package = 2.88 J

the net work done on the package is 2.88 J

b)

let the final speed is v

change in kinetic energy = net work done

0.5 * 2 * v^2 - 0 = 2.88

solving for v

v = 1.7 m/s

the final speed of block is 1.7 m/s

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