The following circuit has the values: V = 40 V, R1 =10?,R2 =20?,R3 =30?,R4 =40?,

Question

The following circuit has the values: V = 40 V, R1 =10?,R2 =20?,R3 =30?,R4 =40?,and R5 = 50 ?.

Compare the current through R1, R2, and R3.

a)I3 <I2 <I1

b)I3 <I2 =I1

c)I3 =I2 <I1

d)I3 =I2 =I1

e)I3 =I2 >I1

Compare the voltage drop across R2, R3, and R4.

a) V4 < V3 = V2

b) V4 > V3 = V2

c) V4 > V3 > V2

d) V4 = V3 = V2

e) V4 = V3 > V2

Calculate the current through R5.

a) 0.19 A

b) 0.29 A

c) 0.39 A

d) 0.49 A

e) 0.59 A

Calculate the voltage drop across R4.

a) 5.8V

b) 10.8 V

c) 15.8 V

d) 20.8 V

e) 25.8 V

Calculate the power dissipated in R3.

a) 0.20 W

b) 0.60 W

c) 1.00 W

d) 1.40 W

e) 1.80 W

Explanation / Answer

Req of circuit

R2 and R3 in series = ( 20 + 30 ) R23 = 50

R23 in parallel with R4 = 50 * 40 / (50+40) = 22.22

R234 , R1 and R5 in series

Req = 82.22

I = 40/82.22 = 0.49 A

part A )

R2 and R3 in series but in parallel with R4 current divide between R4 and R23

I1 > I2 = I3 ( C option )

part b )

R4 and R23 in parallel

R2 and R3 in series , so voltage divide according to resistor

V4 > V3 > V2 ( c option )

part c )

R5 in series so current is 0.49 A ( d option )

part d )

V = IR

R = 22.22

because R4 and R23 in parallel so in parallel voltage remain same

V = 22.22 x 0.49 = 10.8 V ( b option )

part e )

P = V^2/R

V in R3

10.8 divided by ratio

V = 10.8 * 30/50

P = V^2/R

P = 1.40 W ( d option )

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