You have four identical conducting spheres: A, B, C, and D. In each scenario bel
ID: 1357406 • Letter: Y
Question
You have four identical conducting spheres: A, B, C, and D. In each scenario below, sphere A starts with a charge of Q, while B, C, and D start out with no net charge, and then the spheres are touched to each other and separated in the order described. Any spheres not in contact are held very far away. For each scenario, give the final charge of sphere B as a whole number fraction of Q. For example, if you decide that the final charge of sphere B is Q/7, enter "1" in the numerator and "7" in the denominator. Remember! Before each scenario begins, spheres A, B, C, and D are reset to charges of Q, 0, 0, and 0 again.
Scenario 1: A and B touch and are separated, then A and C touch and are separated, then A and D touch and are separated.
Qb= ?/? x Q
Scenario 2: A and B touch and are separated, then B and C touch and are separated, then C and D touch and are separated.
Qb= ?/? x Q
Scenario 3: A and D touch and are separated, then D and C touch and are separated, then D and A touch and are separated, then A and B touch and are separated.
Qb=?/? x Q
Explanation / Answer
by touching total charge will divide in both spheres (same value)
1:
A and B touch
total charge = Q + 0 = Q
charge on both = Q/2
A and C
total charge = Q/2 + 0 = Q/2
charge on both = Q/4
A and D
total charge = Q/4 + 0 = Q/4
charge on both = Q/8 .........Ans
2)
A and B
total charge = Q + 0 = Q
charge on both = Q/2
B and C
total charge = Q/2 + 0 = Q/2
charge on both = Q/4
C and D
total charge = Q/4 + 0 = Q
charge on both = Q/8 ....Ans
3)
A and D
total charge = Q + 0 = Q
charge on both = Q/2
D and C
total charge = Q/2 + 0 = Q/2
charge on both = Q/4
D and A
total charge = Q/4 + Q/2 = 3Q/4
charge on both = 3Q/8
A and B
total charge = 3Q/8 + 0 = 3Q/8
charge on both = 3Q/16 .......Ans
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.