a graph of a position vs time for a moving particle is shown. find the average v

Question

a graph of a position vs time for a moving particle is shown. find the average velocity for t =0 to 4s. Test # 1 Ch 1-3 (10.7)-' x) Take Test: Test 1 Extra Cre x (Vector Addition C f http://blackboard.kea.edu/webapps/assessment take launchjsp?co QUESTION 6 x(m) 10 8 2 0 -2 (s -6 A graph of a position vs time for a moving particle ia shown Find the average velocity for t- 0 to 4 s a10 m/s e c 1.25 m/s o d -25 m/s e -3.33 m/s QUESTION 7 Vector A points north and vector g points east. If -B A then vector C points a south of west b north of east e c south of east. d north of west

Explanation / Answer

here,

let the average velocity be vavg

vavg = total displacemeny /total time taken

for t = 0 to t = 4 s

vavg = 5/4

vavg = 1.25 m/s

the average velocity for the period t = 0 to t = 4 s is 1.25 m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.