A one-legged turkey was sliding across an icy lake at a constant speed of v i =

Question

A one-legged turkey was sliding across an icy lake at a constant speed of vi = 8.83 m/s when it slid onto a 5.20-m wide patch of frozen gravel.
     Use k = 0.5 for the coefficient of kinetic friction between the turkey and the gravel, and g = 9.81 m/s2

Write a symbolic equation for the final velocity, vf, of the turkey in terms of the variables
stated in the problem (i.e. vi, k, g) and the distance, d, that it slid across the gravel.

vf =  

Plug in values to determine the final speed of the one-legged turkey.

vf =  m/s

Explanation / Answer

Deccelartion due to friction , a = - uk g

using vf^2 - vi^2 =2ad

vf^2 - vi^2 =2(-ukg)d

vf = sqrt[ vi^2 - ( 2 uk g d)]

plug in values,

vf = sqrt[ 8.83^2 - ( 2 x 0.5 x 9.81 x 5.20)] = 5.19 m/s

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