A container of 1.00 mole of an ideal gas is compressed from to f along either pa

Question

A container of 1.00 mole of an ideal gas is compressed from to f along either path 1 or path 2, shown on the p-V graph. Assume 3 significant figures for all values on the graph. Circle the correct term within each set of parentheses. Path I is first (isobaric, isochoric, isothermal) and then (isobaric, isochoric, isothermal). The path 2 curve from i to f represents an isothermal process. Determine the temperature along this curve. For each of the paths, 1 and 2, determine (i) the work W done by the gas, (ii) the internal energy change Delta U_int for the gas, and (iii) the heat Q added to the gas.

Explanation / Answer

Path 1 represents isobaric since the pressure is constant and path 2 represents isothermal

For path 2, since it is an isothermal process there is no change in internal energy.

PV=nRT

T=PV/nR

i.e du=0

or Q=w

W=nRTln(vf/vi)

W=10973*103*300*ln(0.04/0.01)=34.10 J

For isobaric,W=pdv

W=1*105*(0.04-0.01)=3000 J

Intrnal energy, U=Q-3000

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