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The sum of all currents entering a control volume, minus the sum of currents lea

ID: 1353987 • Letter: T

Question

The sum of all currents entering a control volume, minus the sum of currents leaving the control volume is always: Increasing if there is a power suppl Constant (not necessarily zero) Decreasing if there is a power supply Zero, only at equilibrium Zero (0.25 points. Attempt 1 of 1.) Following a loop in any circuit, the sum of the voltage increases, minus the sum of all voltage drops is always: Zero, only at equilibrium Zero Increasing if there is a power supply Constant (not necessarily zero) Decreasing if there is a power supply (0.25 points. Attempt 1 of 2.) Refer to the circuit diagram on the right. The power supply V0 has a voltage of 6.98 V, the resistor R, has a resistance of 16800 ohm, and the resistor R2 has a resistance of 19200 ohm. The voltage at Point 1 has a voltage of Vi V; and the voltage at Point 3 has a voltage of 0 V. (0.25 points. Attempt 1 of 1.) Refer to the circuit diagram on the right. The power supply, Vo has a voltage of 3.44 V, and the resistor Ri has a resistance of 11 kohm. Therefore, the voltage drop across the resistor is Vi V. (0.5 points. Attempt 1 of 2.) Refer to the circuit diagram on the right. The power supply, Vo has a voltage of 8.76 V, and the resistor R, has a resistance of 1600 ohm. Therefore, the current across the resistor is h A.

Explanation / Answer

Question (1) According to Kirchoff'e Current Law ,In an electric circuit in steady state the sum of all currents enetering a volume minus all the current leaving the volume is zero.So the correct optin is D.i.e.Zero only at equilibrium.

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