1) For a standard wall clock, the second\'s hand is 11.8 cm long, the minute\'s
ID: 1353241 • Letter: 1
Question
1) For a standard wall clock, the second's hand is 11.8 cm long, the minute's hand is 11.2 cm long whereas the hour's hand is 6.2 cm long. Assuming the three rotate uniformly, enter the speed of the tip of each hand in the answer boxes in the following order: second, minute, hour
Answer 1 of 3:
Answer 2 of 3:
Answer 3 of 3:
2) A kid is standing on the uniformly rotating platform of a carousel. You astutely notice that he can only stand a maximum distance of 0.9 m away from the center of the carousel without slipping. Calculate the coefficient of static friction between the kid's feet and the carousel's platform, if the carousel completes one full rotation in 10 seconds.
Answer:
Explanation / Answer
1)
v(second) = r_seond*w_second = 0.118*(2*pi/60) = 0.0123 m/s
v(minue) = r_minute*w_minute = 0.112*(2*pi/(60*60)) = 1.95*10^-4 m/s
v(hour) = r_hour*w_hour = 0.062*(2*pi/(12*60*60 ) ) = 9.02*10^-6 m/s
2) given time periode, T = 10 s
angular speed, w = 2*pi/T
= 2*pi/10
= 0.628 rad/s
now Apply, static friction = m*a_rad
m*g*mue_s = m*r*w^2
mue_s = r*w^2/g
= 0.9*0.628^2/9.8
= 0.036
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.