A drive is arguing Over his/her cell phone while trailing an unmarked Police car

Question

A drive is arguing Over his/her cell phone while trailing an unmarked Police car by 39m. Both cars are traveling at 29m/s. The argument diverts the drivers attentions from the Police car for 2.5 s. At the beginning of the 2.5 s, the Police officer begins emergency braking at 5.0 m/s. What is the separation vetween the two cars when the drivers attentions finally returns? A drive is arguing Over his/her cell phone while trailing an unmarked Police car by 39m. Both cars are traveling at 29m/s. The argument diverts the drivers attentions from the Police car for 2.5 s. At the beginning of the 2.5 s, the Police officer begins emergency braking at 5.0 m/s. What is the separation vetween the two cars when the drivers attentions finally returns?

Explanation / Answer

distance travelled by driver, d1 = 29*2.5

= 72.5 m

acceleration of police car, a = -5 m/s^2

distance travelled by police car, d2 = u*t + 0.5*a*t^2

= 29*2.5 + 0.5*(-5)*2.5^2

= 56.9 m

so, final separtion = 39 - (d1 - d2)

= 39 - (72.5 - 56.9)

= 23.4 m <<<<<--------Answer

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.