A boy shoves his stuffed toy zebra, which has mass m, down a frictionless chute,

Question

A boy shoves his stuffed toy zebra, which has mass m, down a frictionless chute, starting at a height D above the bottom of the chute and with an initial speed of v. The toy animal emerges horizontally from the bottom of the chute and continues sliding along a horizontal surface with coefficient of kinetic friction . At what distance d from the bottom of the chute does the toy zebra come to rest? Express your answer in terms of the given variables and g, the acceleration due to gravity.

I thought the answer was (0.5v^2+gh)/(mu x g) but it is not correct apparently

Explanation / Answer

let m is the mass of the toy.

Wordkone by friction = change in mechaincal energy

F*d*cos(180) = final mechainical energy - initial mechaincal energy

mue_k*m*g*(-1) = 0 - m*g*D

-mue_k*m*g*d = -m*g*D

mue_k*d = D

d = D/mue_k <<<<<--------Answer

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