Exercise 27.2 A particle with a mass of 1.95×10 4 kg carries a negative charge o

Question

Exercise 27.2

A particle with a mass of 1.95×104 kg carries a negative charge of - 3.10×108 C . The particle is given an initial horizontal velocity that is due north and has a magnitude of 4.35×104 m/s .

Part A

What is the magnitude of the minimum magnetic field that will keep the particle moving in the earth's gravitational field in the same horizontal, northward direction?

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Part B

What is the direction of the minimum magnetic field?

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Exercise 27.2

A particle with a mass of 1.95×104 kg carries a negative charge of - 3.10×108 C . The particle is given an initial horizontal velocity that is due north and has a magnitude of 4.35×104 m/s .

Part A

What is the magnitude of the minimum magnetic field that will keep the particle moving in the earth's gravitational field in the same horizontal, northward direction?

B = T

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Part B

What is the direction of the minimum magnetic field?

What is the direction of the minimum magnetic field? west east north south

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Explanation / Answer

Here ,

let the magnetic field needed is B

for the particle to have constant velocity

net force on the particle

Fnet = 0

mg - q*V*B = 0

1.95 *10^-4 * 9.8 - 3.1 *10^-8 * B * 4.35 *10^4 = 0

B = 1.42 T

the magnetic field needed is 1.42 T

part B)

as force = q * V X B

as force is in upwards direction

the field must be in EAST direction

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