The boom in the figure below (Figure 1) weighs 2600 N and is attached to a frict

Question

The boom in the figure below (Figure 1) weighs 2600 N and is attached to a frictionless pivot at its lower end. It is not uniform; the distance of its center of gravity from the pivot is 32 % of its length.

Part A

Find the tension in the guy wire.

Express your answer in newtons to three significant figures.

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Part B

Find the horizontal component of the force exerted on the boom at its lower end.

Express your answer in newtons to three significant figures.

Part C

Find the vertical component of the force exerted on the boom at its lower end.

Express your answer in newtons to three significant figures.

Explanation / Answer

a) using torque balance through the lower part of the boom :

T*sin(60) = 5000*cos(60) + 0.68*cos(60)*2600

T= 3908 N

b) the horizontal component would be the same as the tension through the Guy wire, since there are no other horizontal forces. so it is 3908 N

c) vertical would be : 5000 + 2600 - 3908 = 3692 N

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