The two wires shown in the figure below are separated by d = 9.6 cm and carry cu

Question

The two wires shown in the figure below are separated by d = 9.6 cm and carry currents of I = 4.75 A in opposite directions.

(a) Find the magnitude and direction of the net magnetic field at a point midway between the wires.

(b) Find the magnitude and direction of the net magnetic field at point P1, 9.6 cm to the right of the wire on the right.

(c) Find the magnitude and direction of the net magnetic field at point P2, 2d = 19.2 cm to the left of the wire on the left.

magnitude µT direction ---Select--- into the page out of the page toward the top of the page toward the bottom of the page toward the left side of the page toward the right side of the page no direction

Explanation / Answer

magnetic field due to each wire is given by B = uo i /2pi r

part Bnet = B1 + B2

Bnet = 4*3.14 e -7 * 4.75 /(2*3.14 *0.048) + 4*3.14 e -7 * 4.75 /2*3.14 *0.048

Bnet = 39.58 uT

no direction

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B. here d1 = 0.096 m and d2 = 2d = 0.192 m

so

Bnet = 4*3.14 e -7 * 4.75 /(2*3.14 *0.096) + 4*3.14 e -7 * 4.75 /(2*3.14 *0.192)

Bnet - 14.84 uT directed to the left
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part C:

d1 = 0.192 m and d2 = 3d = 3 * 0.096 = 0.288 m

so

Bnet = 4*3.14 e -7 * 4.75 /(2*3.14 *0.288) + 4*3.14 e -7 * 4.75 /(2*3.14 *0.192)

Bnet = 8.26 uT

directed to the right

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