In a game of billiards, the cue ball, which has an initial speed of m/s, collide

Question

In a game of billiards, the cue ball, which has an initial speed of m/s, collides with the 8-ball, which is initially at rest. After the collision, the cue ball moves at an angle ? = -o with respect to its original direction, and the 8-ball moves at an angle ? = o with respect to the original direction of the cue ball. You may assume that all billiards balls have the same mass and that the table is frictionless. What is the speed of the cue-ball after the collision? and What is the speed of the 8-ball after the collision?

-593 In a game of billiards the cue ball which has an initial speed of 1.7 ms. collides with the 8-ball vhich is initially at rest. After the collision, the cue ball moves at an angle original direction, and the 8-ball moves at an angle 30.70 with respect to the original direction of the cue ball. with respect to its You may assume that all billards balls have the same mass and that the table is frictionless 1. [2pt] What is the speed of the cue-ball after the collision? Answer: Not yet correct, tries 8/10 2. [2pt] What is the speed of the S-ball after the collision'? Submit All Answers Last Answer: -2.863 m/s Submit All Answers Last Answer: 2.863 m/s

Explanation / Answer

moving in -0 deg by cue ball means it moves in opposite direction

Moving in 0 direction by 8 ball means it moves in its path with out an change in its driection

use the law of conservation of momentum as

m1u1 + m2u2 = m1v1 + m2v2

here m1 = m2 = m and u2 = 0

mu1 + 0 = mv1 + mv2

so u1 = v1 + V2   

using the law of coversation of energy

so 0.5mu1^2 + 0 = 0.5 mv1^2 + 0.5 m2v2^2

as here there wud be exchange of velocities   

speed of cue ball = V1 = 0 m/s

Speed of 8 game ball = u1 or same as that of initial velocity of cue ball

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