A 60 kg woman steps onto an up-going escalator, which has an incline of 32 with

Question

A 60 kg woman steps onto an up-going escalator, which has an incline of 32 with respect to the horizontal and is moving at 0.5 m/s. The top of the escalator is 23 m above the ground level.

alculate how much work is done by gravity, as she moves from the bottom to the top of the escalator.

A) Express your answer in Joules to two significant figures.

B) Calculate how much work is done by the normal force on the woman’s feet, as she moves from the bottom to the top of the escalator.

Express your answer in Joules to two significant figures.

Explanation / Answer

A) Workdone by gravity = -m*g*h

= -60*9.8*23

= -13524 J

= -1.4*10^4 J

B) Workdone by norma force = N*h

= m*g*h

= 13524 J

= 1.4*10^4 J (unsing two significant figures)

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