A 69 kg water skier is being accelerated by a ski boat on a flat (\"glassy\") la

Question

A 69 kg water skier is being accelerated by a ski boat on a flat ("glassy") lake. The coefficient of kinetic friction between the skier's skis and the water surface is k = 0.22.

Part A

What is the skier's acceleration if the rope pulling the skier behind the boat applies a horizontal tension force of magnitude FT = 200 N to the skier (=0)?

Express your answer to two significant figures and include the appropriate units.

aA= __________ in value and units.

Part B

What is the skier's horizontal acceleration if the rope pulling the skier exerts a force of FT = 200 N on the skier at an upward angle = 16 ?

Express your answer to two significant figures and include the appropriate units.

aB = _________ in value and units

Explanation / Answer

Here,

uk = 0.22

for the theta = 0 degree

let the tension in the string is FT = 200 N

Using second law of motion

FT - u* m * g = m * a

200 - 0.22 * 69 * 9.8 = 69 * a

a = 0.74 m/s^2

the acceleration of the skier is 0.74 m/s^2

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