Problem 3.32 A rescue plane wants to drop supplies to isolated mountain climbers

Question

Problem 3.32

A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235 m below. The horizontal velocity of the plane is 250 km/h (69.4 m/s ). Rescue plane releases the supplies a horizontal distance of 425 m in advance of the mountain climbers.
(Figure 1)

Part A

What vertical velocity (up or down) should the supplies be given so that they arrive precisely at the climbers' position (see the figure)?

Express your answer using three significant figures and include the appropriate units.

SubmitHintsMy AnswersGive UpReview Part

Part B

With what speed do the supplies land?

Express your answer using three significant figures and include the appropriate units.

SubmitHintsMy AnswersGive UpReview Part

Provide FeedbackContinue

Figure 1 of 1

Problem 3.32

A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235 m below. The horizontal velocity of the plane is 250 km/h (69.4 m/s ). Rescue plane releases the supplies a horizontal distance of 425 m in advance of the mountain climbers.
(Figure 1)

Part A

What vertical velocity (up or down) should the supplies be given so that they arrive precisely at the climbers' position (see the figure)?

Express your answer using three significant figures and include the appropriate units.

SubmitHintsMy AnswersGive UpReview Part

Part B

With what speed do the supplies land?

Express your answer using three significant figures and include the appropriate units.

vy0 =

SubmitHintsMy AnswersGive UpReview Part

Provide FeedbackContinue

v =

Figure 1 of 1

Explanation / Answer

part(A)

along horizantal

ax = 0

vox = 69.4 m/s

displacement = x = 425 m

x = vox*T

time taken to reach = T = x/vox = 425/69.4 = 6.12 s

along vertical

initial velocity = voy

acceleration ay = -9.8 m/s^2

displacement y = -235 m

y = voy*T + 0.5*ay*T^2

-235 = voy*6.12 - 0.5*9.8*6.12^2

voy = -8.41 m/s (down) <<------------answer

part(B)

after landing

vx = vox + ax*T = 69.4 m/s

along vertical

vy = voy + ay*T

vy = -8.41-(9.8*6.12)

vy = 68.4 m/s

v = sqrt(vx^2+vy^2)

v = sqrt(69.4^2+68.4^2)

v = 97.44 m/s   <<-------------answer

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.