To apply the principle of linear impulse and momentum to a mass to determine the

Question

To apply the principle of linear impulse and momentum to a mass to determine the final speed of the mass. A 10-kg: smooth block moves to the right with a velocity of v_0 m/s when a force F is applied at time t_0 = 0s. At time t_0 = 0 s, a force is applied to the block. If the block is moving with an initial velocity v_0 = 3.25 m/s and the force varies as shown in the graph, (Figure 2), where t_1 = 0.5 s, t_2 = 1 s, and t_3 = 1.5 s, what is the speed of the block at time t_3? Express your answer to three significant figures. The speed of the block at t_3 At time t_0 = 0 s, a force is applied to the block. If the block is moving with an initial velocity v_0 = 2.5 m/s and the force varies as shown in the graph, (Figure 3), where t_1 = 2.25 s, t_2 = 4.5 s, and t_3 = 6.75 s, what is the speed of the block at time t_3? Express your answer to three significant figures. The time it take to stop the motion of the block At time t_0 = 0 s, a force is applied to the block. The force varies as shown in the graph, (Figure 4), where t_1 = 1.25 s, t_2 = 2.5 s, and t_3 = 3.75 s. If the block is moving with an initial velocity v_0 = 3.75 m/s and the force remains constant at -20 N for all times greater than t_3, at what time t_f does the block stop moving to the right? Express your answer to three significant figures.

Explanation / Answer

Please provide me the rest of figure 2,3 and 4 to get complete answer.

You can apply impulse momentum principle to solve problem.

F*dt= mdv

Put force value and integrate equation within time limits to get velocities.

I hope this will help you. I can answer but your question is incomplete.

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