The figure below shows a bar of mass m = 0.280 kg that can slide without frictio

Question

The figure below shows a bar of mass m = 0.280 kg that can slide without friction on a pair of rails separated by a distance l = 1.20 m and located on an inclined plane that makes an angle 6 = 35.0 degree with respect to the ground. The resistance of the resistor is R = 3.30 Ohm, and a uniform magnetic field of magnitude B = 0.500 T is directed downward, perpendicular to the ground, over the entire region through which the bar moves. With what constant speed v does the bar slide along the rails?

Explanation / Answer

let v is the required speed.

induced emf in the rod = B*v*L*sin(90 - 35)

= 0.5*v*1.2**sin(55)

= 0.491*v

power dissipated at resistor = power supplied by the gravity

emf^2/R = F*v

0.491^2*v^2/R = m*g*sin(35)*v

v = m*g*sin(35)*R/0.491^2

= 0.28*9.8*sin(35)*3.3/0.491^2

= 21.5 m/s <<<<<<<----------Answer

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