Object A is moving due east, while object B is moving due north. They collide an
ID: 1344641 • Letter: O
Question
Object A is moving due east, while object B is moving due north. They collide and stick together in a completely inelastic collision. Momentum is conserved. Object A has a mass of mA = 17.6 kg and an initial velocity of nu Overscript bar EndScripts Subscript 0A = 7.35 m/s, due east. Object B, however, has a mass of mB = 29.4 kg and an initial velocity of nu Overscript bar EndScripts Subscript 0B = 5.10 m/s, due north. Find the (a) magnitude and (b) direction of the total momentum of the two-object system after the collision.
Explanation / Answer
momentum is conserved
that is
PA+PB=PA+B
WHERE PA IS THE MOMENTUM OF A
PB =MOMENTUM OF B
BREAK DOWN EACH VECTOR INTO ITS HORIZONTAL AND VERTICLAE COMPONENTS
Momentum of A = 17.6(7.35, 0) where (u, v) means (East, North)
Momentum of B = 29.4(0, 5.10 )
After the objects coalesce they have velocity V = (x, y)
conservation of linear momentum gives
PA+B=SQRT[(17.6*7.35)^2+(29.4*5.10)^2]=198.03 Kg-m/sec
direction=tan^-1(29.4*5.10/17.6*7.35)=49.2 north of east
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