A 25.0-kg block is resting on a flat horizontal table. On top of this block is r

Question

A 25.0-kg block is resting on a flat horizontal table. On top of this block is resting a 10.0-kg block, to which a horizontal spring is attached, as the drawing illustrates. The spring constant of the spring is 315 N/m. The coefficient of kinetic friction between the lower block and the table is 0.470, and the coefficient of static friction between the two blocks is 0.710. A horizontal force is applied to the lower block as shown. This force is increasing in such a way as to keep the blocks moving at a constant speed.
Determine the amount by which the spring is compressed at the point where the upper block begins to slip on the lower block.

Explanation / Answer

When body moves with constant speed

accleration a = 0

so

use from the def of force

F = Kx = u m1 g

x = f m1 g/k

x = 0.71*10*9.8/315

x = - 0.22 m, -ve sign indicates compression

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