Learning Goal: To practice Problem-Solving Strategy 7.1 for interacting- objects

Question

Learning Goal: To practice Problem-Solving Strategy 7.1 for interacting- objects problems. A 1200 -kg car is pushing an out-of-gear 2200 -kg truck that has a dead battery. When the driver steps on the accelerator, the drive wheels of the car push horizontally against the ground with a force of 4520 N . The rolling friction of the car can be neglected, but the heavier truck has a rolling friction of 760 N . including the "friction" of turning the truck's drivetrain. What is the magnitude of the force the car applies to the truck? Correct Significant Figures Feedback: Your answer 3200 N was either rounded differently or used a different number of significant figures than required for this part. Assess Part D What is the acceleration a-r of the truck? Express your answer in meters per second squared to three significant figures.

Explanation / Answer

from force F = ma

accleration of truck a = F/m

a = 3200/2200

a = 1.45 m/s^2

if this happend to be incorrect

you can try

a = 3200/(2200+ 1200)

a = 0.941 m/s^2

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