± A Superball Collides ne!astically with a Table Part A As shown in the figure (
ID: 1340454 • Letter: #
Question
± A Superball Collides ne!astically with a Table Part A As shown in the figure (Figure 1, a superball with mass m equal to 50 grams is dropped from a height of Find the y component of the momentum, Pbeforey, of the ball immediately before the collision. Express your answer numerically, to two significant figures. 1.5 m . It collides with a table, then bounces up to a height of hf1.0 m. The duration of the collision (the time during which the superball is in contact with the table) is te 15 ms. In this problem, take the positive y direction to be upward, and use g 9.8 m/s2 for the magnitude of the acceleration due to gravity. Neglect air resistance Pbefore,y kg m/s Figure 1 of 1 Submit Hints My Answers Give Up Review Part Before During After Part B Find the y component of the momentum of the ball immediately after the collision, that is, just as it is leaving thet Express your answer numerically, to two significant figures. Pafter,y kg m/s Submit Hints My Answers Give Up Review PartExplanation / Answer
(a)
Y component of momentum before collision = - m*v
Using Energy Conservation -
m*g*h = 0.5*m*v^2
v= sqrt(2*g*h)
v = sqrt(2*9.8*1.5)
v = - 5.42 m/s
Y component of momentum before collision = - 50*10^-3 * 5.42 Kgm/s
Y component of momentum before collision = -0.271 Kg m/s
(b)
let the velocity just after collision = Vf
Initial Kinetic Energy = Potential Energy
0.5*m*vf^2 = m*g*h
vf = sqrt(2*g*h)
vf = sqrt(2*9.8*1)
vf = 4.43 m/s
Y component of momentum after collision = 50*10^-3 * 4.43 Kgm/s
Y component of momentum after collision = 0.2215 Kg m/s
(c)
Impulse = Mass*deltaV
Impulse = 50*10^-3 * (4.43 - (-5.42))
Impulse = 0.495 Kg m/s
(d)
Time Average Force , Favg = impuse/time
Favg = 0.495 / 15*10^-3 N
Favg = 33N
(e)
K.E after -K.E before = 0.5*50*10^-3*(4.43^2 - 5.4^2) = - 0.238 J
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