you are looking down on a N = 15 turn coil in a magnetic field B = 1 T which poi

Question

you are looking down on a N = 15 turn coil in a magnetic field B = 1 T which points directly down into the screen. If the diameter of the coil d = 1. 6 cm, and the field goes to zero t = 0. 3 seconds, what would be the magnitude of the voltage and direction of the induced current? Indicate the direction of the current by the sign in front of your voltage: counterclockwise is positive, clockwise is negative. Recall Lenz's Law. Current will flow in such a way as to give rise to a magnetic field that will counteract the change. (Current flows from high potential to low potential.) See the section, "Faraday's Law" for the formulation of this type of problem. Tries 1/12 Previous Tries

Explanation / Answer

Use equation,

e= - N*df/dt = -N*A*dB/dt

N= 15,

r= d/2= 1.6cm/2 = 0.8cm = 0.08m , A= r2= 3.14*0.082 = 0.020096 m2

dB/dt = (0-1)/0.3 = -3.33

e= - N*A*dB/dt = -15*0.020096*-3.33 = + 1.004 V

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